Let x>0x>0x>0, y>0y>0y>0, a>0 a>0\,a>0 and a≠1a\ne1a=1.
Starting from the definition of a logarithm, prove that loga(xy)=logax+logay\log_a(xy)=\log_a x+\log_a yloga(xy)=logax+logay.