Skip to content

Course home

Sign up

1 Unit 1: Pure Mathematics A

EasyMediumHard
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324325326327328329330331332333334335336337338339340341342343344345346347348349350351352353354355356357
Question 275

A scientist monitoring the growth of a synthetic crystal determines that the rate of change of its mass, MMM in milligrams, with respect to time ttt in hours, is given by:

dMdt=5t4−3t34,t>0 \frac{dM}{dt} = 5t^4 - \frac{3}{\sqrt[4]{t^3}}, \quad t > 0 dtdM​=5t4−4t3​3​,t>0

Determine the general expression for the mass M(t)M(t)M(t).

[2]
Markscheme

1 Unit 1: Pure Mathematics A Questions

  1. A Level
  2. /Maths
  3. /1 Unit 1: Pure Mathematics A

Question bank