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1 Unit 1: Pure Mathematics A

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Question 268

Given that x>0 x>0\,x>0 and y>0y>0y>0, simplify (216x627y3)−23\displaystyle \left(\dfrac{216x^6}{27y^3}\right)^{-\frac23}(27y3216x6​)−32​.

[3]
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1 Unit 1: Pure Mathematics A Questions

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