In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2
A tower stands on horizontal ground. The top of the tower is 40 metres above the ground.
A stone A A\,A is released from rest at the top of the tower.
At the same instant, a stone B B\,B is projected vertically upwards from the foot of the tower with speed 20 m s−1^{-1}−1.
Both stones move freely under gravity in the same vertical line.
Show that the two stones are at the same height 2 seconds after they start to move.
Find the height above the ground at which the two stones are at the same height.
State one modelling assumption you have made.
102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.