A particle moves in a straight line, starting from rest.
At time t t\,t seconds, t≥0t \geq 0t≥0, the acceleration of the particle is a=(6−2t)a = (6 - 2t)a=(6−2t) m s−2^{-2}−2.
Find an expression for the velocity of the particle at time ttt.
Find the maximum velocity of the particle.
102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.