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2.7 Kinematics

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Question 21

A particle moves in a straight line so that its velocity at time t t\,t seconds, t≥0t \geq 0t≥0, is v=(3t2−12t+9)v = (3t^2 - 12t + 9)v=(3t2−12t+9) m s−1^{-1}−1

a.

Find the acceleration of the particle when t=1t = 1t=1.

[2]
b.

Find the times at which the particle is instantaneously at rest.

[2]
Markscheme

2.7 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.7 Kinematics

102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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