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2.7 Kinematics

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Question 14
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The velocity of a particle after t t\,t seconds is given by v=(6t−2t2) m s−1v = (6t - 2t^2) \text{ m s}^{-1}v=(6t−2t2) m s−1. When t=0t = 0t=0 the particle is at the origin OOO.

Find the distance of the particle from O O\,O when the particle comes to instantaneous rest.

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Markscheme

2.7 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.7 Kinematics

102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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