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2.7 Kinematics

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Question 22
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The velocity of a particle after t t\,t seconds is given by v=(6t−2t2) m s−1v = (6t - 2t^2) \text{ m s}^{-1}v=(6t−2t2) m s−1. When t=0t = 0t=0 the particle is at the origin OOO.

Find the distance of the particle from O O\,O when the particle comes to instantaneous rest.

[5]

2.7 Kinematics Questions

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