The acceleration of a particle after t t\,t seconds is given by (4t−8) ms−2(4t - 8) \text{ ms}^{-2}(4t−8) ms−2. Given the velocity (vvv) of the particle is 6 ms-1 when t=0t = 0t=0.
Find v v\,v in terms of ttt.
Find the distance between the two points the particle is instantaneously at rest.
102 exam-style questions on WJEC A Level Maths 2.7 Kinematics, covering 2.7.1 Kinematics, 2.7.2 Kinematics, 2.7.3 Kinematics, and 2.7.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.