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1.8 Integration

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Question 4

Given that k k\,k is a positive constant and ∫1k(32x+9)dx=8\displaystyle \int_1^k \left( \frac{3}{2\sqrt{x}} + 9 \right) dx = 8∫1k​(2x​3​+9)dx=8

a.

Show that 9k+3k−20=09k + 3\sqrt{k} - 20 = 09k+3k​−20=0

[4]
b.

Hence, using algebra, find any values of k k\,k such that ∫1k(32x+9)dx=8\displaystyle \int_1^k \left( \frac{3}{2\sqrt{x}} + 9 \right) dx = 8∫1k​(2x​3​+9)dx=8

[4]
Markscheme

1.8 Integration Questions

  1. A Level
  2. /Maths
  3. /1.8 Integration

160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.

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