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1.8 Integration

1.8 Integration

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Question 102

The vertical velocity vvv of a test projectile, in m s−1\text{m s}^{-1}m s−1, is modelled by the function v(t)=t(21−t)v(t) = \sqrt{t}(21 - t)v(t)=t​(21−t) for t≥0t \ge 0t≥0, where ttt is the time in seconds after launch.

a.

Find, using calculus, the time ttt at which the projectile reaches its maximum vertical velocity.

[3]
b.

A graph of vvv against ttt shows a region R1R_1R1​ bounded by the curve and the ttt-axis between t=0t = 0t=0 and the point where the velocity first returns to zero (t=21t = 21t=21). A second region R2R_2R2​ is bounded by the curve, the ttt-axis, and the vertical line t=Kt = Kt=K, where K>21K > 21K>21.

Given that the area of R1R_1R1​ is equal to the area of R2R_2R2​, use calculus to determine the exact value of KKK.

[4]
Markscheme

1.8 Integration Questions

  1. A Level
  2. /Maths
  3. /1.8 Integration

160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.

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