Given that k k\,k is a constant
Find ∫(kx3+2x)dx\displaystyle \int \left( \frac{k}{x^3} + 2x \right) dx∫(x3k+2x)dx Giving your answer in its simplest form.
Find the value of k k\,k such that ∫12(kx3+2x)dx=12\displaystyle \int_1^2 \left( \frac{k}{x^3} + 2x \right) dx = 12∫12(x3k+2x)dx=12
160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.