The point (2,30)(2, 30)(2,30) lies on a curve whose gradient function is dydx=10x4−5\dfrac{dy}{dx} = 10x^4 - 5dxdy=10x4−5
Find an expression for y y\,y in terms of xxx.
160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.