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3.7 Integration (A-level only)

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Question 77

Use the substitution u=6−exu = 6 - e^xu=6−ex to find ∫0ln⁡2ex6−exdx\displaystyle \int_0^{\ln 2} \frac{e^x}{6 - e^x} dx∫0ln2​6−exex​dx

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3.7 Integration (A-level only) Questions

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