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3.7 Integration (A-level only)

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Question 45

Use the substitution x=sin⁡ux = \sin ux=sinu to find ∫02211−x2dx\displaystyle \int_0^{\frac{\sqrt{2}}{2}} \frac{1}{\sqrt{1-x^2}} dx∫022​​​1−x2​1​dx

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3.7 Integration (A-level only) Questions

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