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3.7 Integration (A-level only)

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Question 58

Use the substitution u=6−exu = 6 - e^xu=6−ex to find ∫0ln⁡2ex6−exdx\displaystyle \int_0^{\ln 2} \frac{e^x}{6 - e^x} dx∫0ln2​6−exex​dx

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3.7 Integration (A-level only) Questions

  1. A Level
  2. /Maths
  3. /3.7 Integration (A-level only)

221 exam-style questions on WJEC A Level Maths 3.7 Integration (A-level only), covering 3.7.1 Integration (A-level only), 3.7.2 Integration (A-level only), 3.7.3 Integration (A-level only), 3.7.4 Integration (A-level only), 3.7.5 Integration (A-level only), and 3.7.6 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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