Find the exact value of ∫244x2−3x+5(x−1)2(x+2)dx\displaystyle \int_2^4 \frac{4x^2 - 3x + 5}{(x-1)^2(x+2)} dx∫24(x−1)2(x+2)4x2−3x+5dx
221 exam-style questions on WJEC A Level Maths 3.7 Integration (A-level only), covering 3.7.1 Integration (A-level only), 3.7.2 Integration (A-level only), 3.7.3 Integration (A-level only), 3.7.4 Integration (A-level only), 3.7.5 Integration (A-level only), and 3.7.6 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.