1.5 Trigonometry

78%

a.

Show that the equation

6\cos^2 x = 4 - \sin x

Can be written in the form

6\sin^2 x - \sin x - 2 = 0

[3]

b.

Hence solve, for $\leq x < 360^\circ$ , the equation,

6\cos^2 x = 4 - \sin x

Give your answers to one decimal place where appropriate.

[6]

78%

a.

Show that the equation

6\cos^2 x = 4 - \sin x

Can be written in the form

6\sin^2 x - \sin x - 2 = 0

[3]

b.

Hence solve, for $\leq x < 360^\circ$ , the equation,

6\cos^2 x = 4 - \sin x

Give your answers to one decimal place where appropriate.

[6]

1.5 Trigonometry Questions