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1.5 Trigonometry

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Question 28
a.

Given that θ \theta\,θ is small, use the small angle approximation of cos⁡θ \cos \theta\,cosθ to show that

5cos⁡(θ)−cos⁡2(2θ)≈4+1.5θ2−4θ4 5 \cos(\theta) - \cos^2(2\theta) \approx 4 + 1.5\theta^2 - 4\theta^4 5cos(θ)−cos2(2θ)≈4+1.5θ2−4θ4
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b.

Hence find an approximation of 5cos⁡(θ)−cos⁡2(2θ)5 \cos(\theta) - \cos^2(2\theta)5cos(θ)−cos2(2θ) when θ=2∘\theta = 2^\circθ=2∘

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c.

Calculate the percentage error in your approximation

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1.5 Trigonometry Questions

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