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1.5 Trigonometry

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Question 48

Solve, for 0≤x≤3600 \leq x \leq 3600≤x≤360, the equation,

2tan⁡2x+7sec⁡x+1=0 2\tan^2x + 7\sec x + 1 = 0 2tan2x+7secx+1=0

Give your answers to 1 decimal place.

[5]

1.5 Trigonometry Questions

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