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Trigonometric Identities and Equations

Trigonometric Identities and Equations

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Question 22
a.

Show that the equation

3sin⁡2xtan⁡2x=cos⁡2x+2 3\sin 2x\tan 2x=\cos 2x+2 3sin2xtan2x=cos2x+2

can be written in the form

4cos⁡22x+2cos⁡2x−3=0. 4\cos^2 2x+2\cos 2x-3=0. 4cos22x+2cos2x−3=0.
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b.

Find all values of x x\,x in the interval 0≤x<180∘ 0\leq x<180^\circ\,0≤x<180∘ for which

3sin⁡2xtan⁡2x=cos⁡2x+2. 3\sin 2x\tan 2x=\cos 2x+2. 3sin2xtan2x=cos2x+2.

Give your answers to two decimal places.

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Markscheme

Trigonometric Identities and Equations Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Identities and Equations

41 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.

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