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Trigonometric Identities and Equations

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Question 97
a.

Show that the equation 3sin⁡2xtan⁡2x=cos⁡2x+23\sin 2x \tan 2x = \cos 2x + 23sin2xtan2x=cos2x+2 can be written in the form 4cos⁡22x+2cos⁡2x−3=04\cos^2 2x + 2\cos 2x - 3 = 04cos22x+2cos2x−3=0

[4]
b.

Solve the equation 4y2+2y−3=04y^2 + 2y - 3 = 04y2+2y−3=0, giving your answers in exact form.

[2]
c.

Hence find all values for x x\,x in the interval 0≤x<180∘0 \leq x < 180^\circ0≤x<180∘, for which 3sin⁡2xtan⁡2x=cos⁡2x+23\sin 2x \tan 2x = \cos 2x + 23sin2xtan2x=cos2x+2. Give your answers to two decimal places.

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Markscheme

Trigonometric Identities and Equations Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Identities and Equations

322 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.

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