Question 37
The diagram shows parts of the curves y=6cos2θy = 6\cos^2\thetay=6cos2θ and y=5−tanθcosθy = 5 - \tan\theta \cos\thetay=5−tanθcosθ, where θ \theta\,θ is in degrees.
a.[2]
Show that the equation 5−tanθcosθ=6cos2θ5 - \tan\theta \cos\theta = 6\cos^2\theta5−tanθcosθ=6cos2θ can be expressed in the form 6sin2x−sinx−1=06\sin^2 x - \sin x - 1 = 06sin2x−sinx−1=0
b.[5]
Solve the inequality 5−tanθcosθ>6cos2θ5 - \tan\theta \cos\theta > 6\cos^2\theta5−tanθcosθ>6cos2θ for 0∘≤θ<360∘0^\circ \leq \theta < 360^\circ0∘≤θ<360∘
Trigonometric Identities and Equations Questions
41 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.