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Conditional Probability

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Question 28

The events A A\,A and B B\,B are such that P(A)=0.2P(A) = 0.2P(A)=0.2 and P(A∪B)=0.6P(A \cup B) = 0.6P(A∪B)=0.6. Find

a.

P(A′∩B′)P(A' \cap B')P(A′∩B′)

[2]
b.

P(A′∩B)P(A' \cap B)P(A′∩B)

[2]
c.

Given also that the events A A\,A and B B\,B are independent, find P(B)P(B)P(B)

[4]
d.

P(A′∪B′)P(A' \cup B')P(A′∪B′)

[2]

Conditional Probability Questions

  1. A Level
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  3. /Conditional Probability