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Conditional Probability

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Question 11

The events X X\,X and Y Y\,Y are such that P(X)=0.4P(X) = 0.4P(X)=0.4 and P(X∪Y)=0.8P(X \cup Y) = 0.8P(X∪Y)=0.8.

a.

Find P(X′∩Y′)P(X' \cap Y')P(X′∩Y′).

[2]
b.

Find P(X′∩Y)P(X' \cap Y)P(X′∩Y).

[2]
c.

Given also that the events X X\,X and Y Y\,Y are independent, find P(Y)P(Y)P(Y).

[4]
d.

Find P(X′∪Y′)P(X' \cup Y')P(X′∪Y′).

[2]

Conditional Probability Questions

  1. A Level
  2. /Maths
  3. /Conditional Probability