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Further Kinematics

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Question 45

An automated research probe is navigating through a tidal stream with an initial velocity of (7i+2j) m s−1(7\mathbf{i} + 2\mathbf{j}) \text{ m s}^{-1}(7i+2j) m s−1.

The acceleration a m s−2\mathbf{a} \text{ m s}^{-2}a m s−2 of the probe at time ttt seconds is given by

a=(15kt2−12kt+6)i \mathbf{a} = (15kt^2 - 12kt + 6)\mathbf{i} a=(15kt2−12kt+6)i

where kkk is a constant and i\mathbf{i}i and j\mathbf{j}j are perpendicular horizontal unit vectors.

When t=3t = 3t=3, the velocity of the probe is (43i+2j) m s−1(43\mathbf{i} + 2\mathbf{j}) \text{ m s}^{-1}(43i+2j) m s−1.

Show that k=29k = \frac{2}{9}k=92​.

[5]

Further Kinematics Questions

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