A particle moves in a straight line relative to an origin OOO. The displacement, sss metres, of the particle from OOO at time ttt seconds is given by
s=p+5t−ke−0.4t s = p + 5t - ke^{-0.4t} s=p+5t−ke−0.4twhere ppp and kkk are constants. At time t=2t = 2t=2, the acceleration of the particle is −2.4 m s−2-2.4\text{ m s}^{-2}−2.4 m s−2.
Show that k≈33.4k \approx 33.4k≈33.4
Given that the particle has an initial displacement of 8 metres, find the value of ppp. Give your answer to two significant figures.