g(x)=ln(3x−1)+x2−6x>13\displaystyle g(x) = \ln(3x - 1) + x^2 - 6 \quad x > \frac{1}{3}g(x)=ln(3x−1)+x2−6x>31
Show that g(x)=0g(x) = 0g(x)=0 has a root in the interval [2.0,2.1][2.0, 2.1][2.0,2.1]
Find g′(x)g'(x)g′(x)
Using x0=2.0x_0 = 2.0x0=2.0 as a first approximation, apply the Newton-Raphson procedure to find a second approximation, giving your answer to 3 decimal places.
Practise AQA A Level Maths 1.12 I: Numerical methods (A-level only) with exam-style questions for A Level Maths. 107 questions covering 1.12.1 Locating roots by change of sign (A-level only), 1.12.2 Iterative methods and Newton-Raphson (A-level only), 1.12.3 Numerical integration (A-level only), and 1.12.4 Numerical methods in context (A-level only), matched to the AQA A Level Maths (7357) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.