Show that the equation
6sinθcosθcosθ+sinθ=(4+2sec2θ)(cosθ−sinθ) \frac{6 \sin \theta \cos \theta}{\cos \theta + \sin \theta} = (4 + 2\sec 2\theta)(\cos \theta - \sin \theta) cosθ+sinθ6sinθcosθ=(4+2sec2θ)(cosθ−sinθ)can be written in the form
3sin2θ−4cos2θ=2 3 \sin 2\theta - 4 \cos 2\theta = 2 3sin2θ−4cos2θ=2Hence solve for 0<x<π0 < x < \pi0<x<π
6sinxcosxcosx+sinx=(4+2sec2x)(cosx−sinx) \frac{6 \sin x \cos x}{\cos x + \sin x} = (4 + 2\sec 2x)(\cos x - \sin x) cosx+sinx6sinxcosx=(4+2sec2x)(cosx−sinx)giving your answers to 3 significant figures.
317 exam-style questions on AQA A Level Maths 1.8 E: Trigonometry, covering 1.8.1 Trigonometric definitions, rules and radians, 1.8.2 Small angle approximations (A-level only), 1.8.3 Trigonometric functions and exact values, 1.8.4 Reciprocal and inverse trigonometric functions (A-level only), 1.8.5 Trigonometric identities, 1.8.6 Compound and double angle formulae (A-level only), 1.8.7 Solving trigonometric equations, 1.8.8 Proofs with trigonometric identities, and 1.8.9 Trigonometry in context. Each one has a worked solution and a mark scheme showing where the marks go.