A signal processing algorithm converts an input voltage vvv into a compressed metric M(v)M(v)M(v) using the formula:
M(v)=ev/4+10 M(v) = e^{v/4} + 10 M(v)=ev/4+10for v∈Rv \in \mathbb{R}v∈R.
Identify the expression for the inverse function M−1(x)M^{-1}(x)M−1(x).
Tick (✓\checkmark✓) one box.
□M−1(x)=4ln(x)−10\square \quad M^{-1}(x) = 4\ln(x) - 10□M−1(x)=4ln(x)−10
□M−1(x)=1ex/4+10\square \quad M^{-1}(x) = \frac{1}{e^{x/4} + 10}□M−1(x)=ex/4+101
□M−1(x)=4ln(x−10)\square \quad M^{-1}(x) = 4\ln(x - 10)□M−1(x)=4ln(x−10)
□M−1(x)=ln(x−10)+4\square \quad M^{-1}(x) = \ln(x - 10) + 4□M−1(x)=ln(x−10)+4
532 exam-style questions on AQA A Level Maths 1.5 B: Algebra and functions, covering 1.5.1 Laws of indices, 1.5.2 Surds, 1.5.3 Quadratic functions, 1.5.4 Simultaneous equations, 1.5.5 Linear and quadratic inequalities, 1.5.6 Polynomials and rational expressions, 1.5.7 Graphs of functions and proportion, 1.5.8 Composite and inverse functions (A-level only), 1.5.9 Transformations of graphs, 1.5.10 Partial fractions (A-level only), and 1.5.11 Functions in modelling (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.