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Redox

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Question 12

In the adduct compound [XeF5]+[RuF6]−[\text{XeF}_5]^+ [\text{RuF}_6]^-[XeF5​]+[RuF6​]−, the oxidation number of fluorine is -1.

What are the oxidation numbers of Xe\text{Xe}Xe and Ru\text{Ru}Ru in this compound?

A

Xe=+4\text{Xe} = +4Xe=+4 and Ru=+6\text{Ru} = +6Ru=+6

B

Xe=+6\text{Xe} = +6Xe=+6 and Ru=+5\text{Ru} = +5Ru=+5

C

Xe=+5\text{Xe} = +5Xe=+5 and Ru=+6\text{Ru} = +6Ru=+6

D

Xe=+6\text{Xe} = +6Xe=+6 and Ru=+6\text{Ru} = +6Ru=+6

Markscheme

Redox Questions

  1. A Level
  2. /Chemistry
  3. /Redox

26 exam-style questions on OCR A A Level Chemistry Redox. Each one has a worked solution and a mark scheme showing where the marks go.

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