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Question 13

In the compound [ICl2]+[FeCl4]−[\text{ICl}_2]^+ [\text{FeCl}_4]^-[ICl2​]+[FeCl4​]−, the oxidation number of chlorine is -1.

What are the oxidation numbers of I\text{I}I and Fe\text{Fe}Fe in the compound?

I=+1\text{I} = +1I=+1, Fe=+3\text{Fe} = +3Fe=+3

I=+3\text{I} = +3I=+3, Fe=+2\text{Fe} = +2Fe=+2

I=+3\text{I} = +3I=+3, Fe=+3\text{Fe} = +3Fe=+3

I=+1\text{I} = +1I=+1, Fe=+2\text{Fe} = +2Fe=+2

Redox Questions

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