In the compound [ICl2]+[FeCl4]−[\text{ICl}_2]^+ [\text{FeCl}_4]^-[ICl2]+[FeCl4]−, the oxidation number of chlorine is -1.
What are the oxidation numbers of I\text{I}I and Fe\text{Fe}Fe in the compound?
I=+1\text{I} = +1I=+1, Fe=+3\text{Fe} = +3Fe=+3
I=+3\text{I} = +3I=+3, Fe=+2\text{Fe} = +2Fe=+2
I=+3\text{I} = +3I=+3, Fe=+3\text{Fe} = +3Fe=+3
I=+1\text{I} = +1I=+1, Fe=+2\text{Fe} = +2Fe=+2