In the ionic compound [VO2]+[FeCl4]−[\text{VO}_2]^+ [\text{FeCl}_4]^-[VO2]+[FeCl4]−, the oxidation number of oxygen is -2 and that of chlorine is -1.
What are the oxidation numbers of vanadium (V\text{V}V) and iron (Fe\text{Fe}Fe) in this compound?
V=+4\text{V} = +4V=+4 and Fe=+2\text{Fe} = +2Fe=+2
V=+5\text{V} = +5V=+5 and Fe=+3\text{Fe} = +3Fe=+3
V=+3\text{V} = +3V=+3 and Fe=+3\text{Fe} = +3Fe=+3
V=+5\text{V} = +5V=+5 and Fe=+5\text{Fe} = +5Fe=+5
