Enthalpy values are provided below.
H2(g)+Br2(g)→2HBr(g)ΔrH=−103 kJ mol−1 \text{H}_2(\text{g}) + \text{Br}_2(\text{g}) \rightarrow 2\text{HBr}(\text{g}) \quad \Delta_r H = -103 \text{ kJ mol}^{-1} H2(g)+Br2(g)→2HBr(g)ΔrH=−103 kJ mol−1Bond enthalpies: H−H=+436 kJ mol−1\text{H}-\text{H} = +436 \text{ kJ mol}^{-1}H−H=+436 kJ mol−1, Br−Br=+193 kJ mol−1\text{Br}-\text{Br} = +193 \text{ kJ mol}^{-1}Br−Br=+193 kJ mol−1.
What is the bond enthalpy, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1, of the H−Br\text{H}-\text{Br}H−Br bond?
−732-732−732
−366-366−366
+366+366+366
+732+732+732
