Barium hydroxide reacts with hydrochloric acid according to the equation:
Ba(OH)2(aq)+2HCl(aq)→BaCl2(aq)+2H2O(l) \text{Ba(OH)}_2(\text{aq}) + 2\text{HCl}(\text{aq}) \rightarrow \text{BaCl}_2(\text{aq}) + 2\text{H}_2\text{O}(\text{l}) Ba(OH)2(aq)+2HCl(aq)→BaCl2(aq)+2H2O(l)A volume of 60.0 cm3 of 0.25 mol dm-3 Ba(OH)2\text{Ba(OH)}_2Ba(OH)2 is fully neutralised by excess HCl\text{HCl}HCl. The heat energy given out during this reaction is 1.71 kJ.
What is the enthalpy change of neutralisation, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1?
−114.0-114.0−114.0
−57.0-57.0−57.0
+57.0+57.0+57.0
+114.0+114.0+114.0
