The equation for the combustion of ethanol, C2H5OH\text{C}_2\text{H}_5\text{OH}C2H5OH, is shown below: \
\text{C}_2\text{H}_5\text{OH(l)} + 3\text{O}_2\text{(g)} \\rightarrow 2\text{CO}_2\text{(g)} + 3\text{H}_2\text{O(l)}{\char"24}$ Enthalpy changes of formation are shown in the table: \\begin{array}{|c|c|c|c|} \hline \text{Substance} & \text{C}_2\text{H}_5\text{OH(l)} & \text{CO}_2\text{(g)} & \text{H}2\text{O(l)} \\ \hline \Delta{\text{f}}H\text{ / kJ mol}^{-1} & -277 & -394 & -286 \\ \hline \end{array}{\char"24}Calculatetheenthalpyofcombustion,inCalculate the enthalpy of combustion, inCalculatetheenthalpyofcombustion,in\text{kJ mol}^{-1}$, for ethanol.
