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Atoms and reactions

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Question 93

A student prepares nitrobenzene by reacting 15.6 g of benzene with excess concentrated nitric acid according to the equation below:

C6H6+HNO3→C6H5NO2+H2O \text{C}_6\text{H}_6 + \text{HNO}_3 \rightarrow \text{C}_6\text{H}_5\text{NO}_2 + \text{H}_2\text{O} C6​H6​+HNO3​→C6​H5​NO2​+H2​O Mr(C6H6)=78.0Mr(C6H5NO2)=123.0 M_r(\text{C}_6\text{H}_6) = 78.0 \qquad M_r(\text{C}_6\text{H}_5\text{NO}_2) = 123.0 Mr​(C6​H6​)=78.0Mr​(C6​H5​NO2​)=123.0

The reaction produces 18.45 g of nitrobenzene.

What is the percentage yield of nitrobenzene?

A

63.4%63.4\%63.4%

B

75.0%75.0\%75.0%

C

84.6%84.6\%84.6%

D

53.6%53.6\%53.6%

Markscheme

Atoms and reactions Questions

  1. A Level
  2. /Chemistry
  3. /Atoms and reactions

199 exam-style questions on OCR A A Level Chemistry Atoms and reactions, covering Atomic structure and isotopes, Compounds, formulae and equations, Amount of substance, Acids, and Redox. Each one has a worked solution and a mark scheme showing where the marks go.

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