A student reacts 1.18 g of trimethylamine gas, (CH3)3N(\text{CH}_3)_3\text{N}(CH3)3N (Mr=59.0M_{\text{r}} = 59.0Mr=59.0), with 40 cm3 of 0.80 mol dm-3 hydrochloric acid to produce a solution of trimethylammonium chloride.
(CH3)3N(g)+HCl(aq)→(CH3)3NH+(aq)+Cl−(aq) (\text{CH}_3)_3\text{N}(\text{g}) + \text{HCl}(\text{aq}) \rightarrow (\text{CH}_3)_3\text{NH}^+(\text{aq}) + \text{Cl}^-(\text{aq}) (CH3)3N(g)+HCl(aq)→(CH3)3NH+(aq)+Cl−(aq)Assuming the volume of the solution does not change upon dissolving the gas, what is the concentration of trimethylammonium chloride in the resulting solution?
0.020.020.02
0.300.300.30
0.500.500.50
0.800.800.80
199 exam-style questions on OCR A A Level Chemistry Atoms and reactions, covering Atomic structure and isotopes, Compounds, formulae and equations, Amount of substance, Acids, and Redox. Each one has a worked solution and a mark scheme showing where the marks go.