The theoretical EMF of a hydrazine–oxygen fuel cell operating under alkaline conditions is +1.56 V+1.56\text{ V}+1.56 V.
The standard electrode potential for one of the electrodes in this cell is:
N2(g)+4H2O(l)+4e−→N2H4(aq)+4OH−(aq)E⊖=−1.16 V \text{N}_2\text{(g)} + 4\text{H}_2\text{O(l)} + 4\text{e}^- \rightarrow \text{N}_2\text{H}_4\text{(aq)} + 4\text{OH}^-\text{(aq)} \quad E^\ominus = -1.16\text{ V} N2(g)+4H2O(l)+4e−→N2H4(aq)+4OH−(aq)E⊖=−1.16 VGive the half-equation for the other electrode and calculate its standard electrode potential.