The theoretical EMF of a direct ethanol fuel cell operating under acidic conditions is +1.15 V.
The standard electrode potential for one of the electrodes in this cell is:
2CO2(g)+12H+(aq)+12e−→CH3CH2OH(aq)+3H2O(l)E⊖=+0.08 V 2\text{CO}_2\text{(g)} + 12\text{H}^+\text{(aq)} + 12\text{e}^- \rightarrow \text{CH}_3\text{CH}_2\text{OH(aq)} + 3\text{H}_2\text{O(l)} \quad E^\ominus = +0.08\text{ V} 2CO2(g)+12H+(aq)+12e−→CH3CH2OH(aq)+3H2O(l)E⊖=+0.08 VGive the half-equation for the other electrode and calculate its standard electrode potential.