What is the minimum volume, in cm3\text{cm}^3cm3, of 0.025 mol dm-3 KMnO4\text{KMnO}_4KMnO4 solution needed to oxidise 0.015 mol of C2O42−\text{C}_2\text{O}_4^{2-}C2O42− ions?
2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2O 2\text{MnO}_4^- + 5\text{C}_2\text{O}_4^{2-} + 16\text{H}^+ \rightarrow 2\text{Mn}^{2+} + 10\text{CO}_2 + 8\text{H}_2\text{O} 2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2O120120120
240240240
600600600
150015001500