Amount of substance

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Question 40
Medium

The reaction between manganate(VII) ions and ethanedioate ions in acidic solution can be represented by the equation:

2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2O 2\text{MnO}_4^{-} + 5\text{C}_2\text{O}_4^{2-} + 16\text{H}^+ \rightarrow 2\text{Mn}^{2+} + 10\text{CO}_2 + 8\text{H}_2\text{O} 2MnO4−​+5C2​O42−​+16H+→2Mn2++10CO2​+8H2​O

What volume, in dm3\text{dm}^3dm3, of 0.025 mol dm-3 KMnO4\text{KMnO}_4KMnO4​ is needed to react completely with 0.075 mol of sodium ethanedioate (Na2C2O4\text{Na}_2\text{C}_2\text{O}_4Na2​C2​O4​)?

0.480.480.48

1.21.21.2

3.03.03.0

7.57.57.5

Amount of substance Questions

  1. A Level
  2. /Chemistry
  3. /Amount of substance