The reaction between manganate(VII) ions and ethanedioate ions in acidic solution can be represented by the equation:
2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2O 2\text{MnO}_4^{-} + 5\text{C}_2\text{O}_4^{2-} + 16\text{H}^+ \rightarrow 2\text{Mn}^{2+} + 10\text{CO}_2 + 8\text{H}_2\text{O} 2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2OWhat volume, in dm3\text{dm}^3dm3, of 0.025 mol dm-3 KMnO4\text{KMnO}_4KMnO4 is needed to react completely with 0.075 mol of sodium ethanedioate (Na2C2O4\text{Na}_2\text{C}_2\text{O}_4Na2C2O4)?
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