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Amount of substance

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Question 3

The equation for the complete combustion of gaseous methylamine is:

4CH3NH2(g)+9O2(g)→4CO2(g)+10H2O(g)+2N2(g) 4\text{CH}_3\text{NH}_2(\text{g}) + 9\text{O}_2(\text{g}) \rightarrow 4\text{CO}_2(\text{g}) + 10\text{H}_2\text{O}(\text{g}) + 2\text{N}_2(\text{g}) 4CH3​NH2​(g)+9O2​(g)→4CO2​(g)+10H2​O(g)+2N2​(g)

What is the mole fraction of methylamine in a gaseous reactant mixture containing the minimum quantity of oxygen required for complete combustion?

A

0.1380.1380.138

B

0.3080.3080.308

C

0.4440.4440.444

D

0.6920.6920.692

Markscheme

Amount of substance Questions

  1. A Level
  2. /Chemistry
  3. /Amount of substance

79 exam-style questions on AQA A Level Chemistry Amount of substance, covering Relative atomic mass and relative molecular mass, The mole and the Avogadro constant, The ideal gas equation, Empirical and molecular formula, and Balanced equations and associated calculations. Each one has a worked solution and a mark scheme showing where the marks go.

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