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Motion in the universe

What you'll learn

  • How the Universe, galaxies, stars and our Solar System fit together.
  • Why gravitational field strength, ggg, is different on different worlds.
  • How gravity keeps planets, moons, comets and satellites in orbit.
  • How to calculate orbital speed using orbital radius and time period.

The big picture: Universe, galaxies and the Solar System

The Universe is everything that exists: all space, matter and energy. It contains a huge number of galaxies.

A galaxy is a very large collection of billions of stars, held together by gravity. Our galaxy is the Milky Way.

Our Solar System is the Sun and the objects that orbit it, including planets, moons, comets and artificial satellites. It is located inside the Milky Way galaxy.

Nested diagram showing the Universe containing many galaxies, the Milky Way containing our Solar System, and the Solar System containing the Sun, planets, moons, comets and artificial satellites

Key Idea

Cosmic address

Universe → galaxies → Milky Way galaxy → Solar System → Earth.

Gravitational field strength, ggg

Gravity is an attractive force between masses. Around any planet, moon or star there is a gravitational field: a region where another mass experiences a gravitational force.

Definition

Gravitational field strength

Gravitational field strength, ggg, is the gravitational force on each kilogram of mass. Its unit is N/kg.

On Earth, ggg is about 9.8 N/kg, often rounded to 10 N/kg in IGCSE calculations. On the Moon, ggg is about 1.6 N/kg.

Gravitational field strength varies because different planets and moons have different masses and sizes. In general:

  • a more massive body produces a stronger gravitational field
  • further from the centre of a body, the gravitational field is weaker
  • surface gravity depends on both the body’s mass and its radius

So ggg is not the same on Earth, the Moon, Mars or Jupiter.

You may use the earlier equation:

weight = mass × gravitational field strength

W=m×gW = m \times gW=m×g

where weight, WWW, is in N, mass, mmm, is in kg, and gravitational field strength, ggg, is in N/kg.

Example

Comparing weight on Earth and the Moon

An astronaut has mass 60 kg. Calculate their weight on Earth, where g=10 N/kgg = 10\ \text{N/kg}g=10 N/kg, and on the Moon, where g=1.6 N/kgg = 1.6\ \text{N/kg}g=1.6 N/kg.

  1. Use the relationship W=m×gW = m \times gW=m×g. The astronaut’s mass stays 60 kg, but ggg changes from place to place.
  2. On Earth: W=60 kg×10 N/kg=600 NW = 60\ \text{kg} \times 10\ \text{N/kg} = 600\ \text{N}W=60 kg×10 N/kg=600 N.
  3. On the Moon: W=60 kg×1.6 N/kg=96 NW = 60\ \text{kg} \times 1.6\ \text{N/kg} = 96\ \text{N}W=60 kg×1.6 N/kg=96 N.
  4. The astronaut weighs much less on the Moon because the Moon has a weaker gravitational field.
Common Mistake

Mass is not weight

Mass is the amount of matter in an object and is measured in kg. Weight is a gravitational force and is measured in N. Your mass stays the same on the Moon; your weight changes.

Gravity and orbits

An orbit is the path followed by an object as it moves around another object in space.

Gravity causes:

  • moons to orbit planets
  • planets to orbit the Sun
  • artificial satellites to orbit the Earth
  • comets to orbit the Sun

For an object in orbit, gravity acts towards the body being orbited. For example, Earth’s gravity pulls an artificial satellite towards the centre of the Earth.

The satellite also has sideways motion. Gravity continually changes the satellite’s direction, so instead of travelling in a straight line, it follows a curved path around Earth.

Diagram of planets, comets, moons and artificial satellites in orbit, showing gravitational force towards the central body and velocity tangent to the orbit

Key Idea

Gravity provides the inward force

In an orbit, the gravitational force acts towards the centre of the object being orbited. The velocity is along the path, at a tangent to the orbit.

Example

Determining force and velocity directions

A satellite is at the top of a circular orbit around Earth and is moving clockwise. State the direction of the gravitational force and the direction of its velocity.

  1. The central body is Earth, so the gravitational force must act towards the centre of Earth.
  2. At the top of the orbit, Earth is below the satellite, so the gravitational force is downwards on the diagram.
  3. The velocity is tangent to the circular path. For clockwise motion at the top of the orbit, the velocity is to the right.
Common Mistake

Thinking there is no gravity in space

Objects in orbit are not “outside gravity”. They are still being pulled by gravity. Without gravity, they would travel off in a straight line.

Different types of orbit

Not all objects orbit in the same way.

Definition

Elliptical orbit

An elliptical orbit is an oval-shaped orbit. A circle is a special case of an ellipse.

ObjectWhat it orbitsTypical orbit
PlanetThe SunNearly circular or slightly elliptical
MoonA planetUsually roughly circular or slightly elliptical
Artificial satelliteEarth or another planetOften circular or slightly elliptical, depending on its purpose
CometThe SunVery elongated elliptical orbit

Planets move around the Sun in paths that are almost circular compared with comets. Comets often travel very far from the Sun, then swing close to the Sun before moving away again. Their speed changes a lot: they are fastest when closest to the Sun.

Moons are natural satellites because they orbit planets naturally. Artificial satellites are human-made objects placed into orbit, for example for communications, weather monitoring or GPS.

Example

Distinguishing a planet and a comet

Two objects orbit the Sun. Object A has a nearly circular orbit. Object B has a very stretched oval orbit and returns close to the Sun only after many years. Identify which is more likely to be a planet and which is more likely to be a comet.

  1. Both objects orbit the Sun, so either could be a planet or a comet.
  2. Object A has a nearly circular orbit, which matches the usual orbit of a planet.
  3. Object B has a very elongated elliptical orbit, which is typical of a comet.
  4. Therefore, Object A is more likely to be a planet and Object B is more likely to be a comet.

Calculating orbital speed

For a circular orbit, the distance travelled in one complete orbit is the circumference of the circle.

Circumference of orbit = 2×π×r2 \times \pi \times r2×π×r

where rrr is the orbital radius, the distance from the centre of the object being orbited to the orbiting object.

Definition

Time period

The time period, TTT, is the time taken for one complete orbit.

The Edexcel relationship is:

orbital speed = 2 × π × orbital radius ÷ time period

v=2×π×rTv = \frac{2 \times \pi \times r}{T}v=T2×π×r​

where:

  • vvv = orbital speed in m/s
  • rrr = orbital radius in m
  • TTT = time period in s

You may need these rearrangements:

v=2×π×rTT=2×π×rvr=v×T2×π\begin{aligned} v &= \frac{2 \times \pi \times r}{T}\\ T &= \frac{2 \times \pi \times r}{v}\\ r &= \frac{v \times T}{2 \times \pi} \end{aligned}vTr​=T2×π×r​=v2×π×r​=2×πv×T​​
Example

Calculating orbital speed

A satellite moves in a circular orbit of radius 7000 km from the centre of Earth. Its time period is 5800 s. Calculate its orbital speed.

  1. Convert the radius into metres: 7000 km=7.0×106 m7000\ \text{km} = 7.0 \times 10^6\ \text{m}7000 km=7.0×106 m.
  2. Use v=2×π×rTv = \frac{2 \times \pi \times r}{T}v=T2×π×r​ with r=7.0×106 mr = 7.0 \times 10^6\ \text{m}r=7.0×106 m and T=5800 sT = 5800\ \text{s}T=5800 s.
  3. Substitute values: v=2×π×7.0×106 m5800 sv = \frac{2 \times \pi \times 7.0 \times 10^6\ \text{m}}{5800\ \text{s}}v=5800 s2×π×7.0×106 m​.
  4. Calculate: v=7.6×103 m/sv = 7.6 \times 10^3\ \text{m/s}v=7.6×103 m/s, to 2 significant figures.
Tip

Unit check

If rrr is in m and TTT is in s, the answer comes out in m/s. Convert km to m, and convert hours or days to seconds if needed.

Common Mistake

Altitude is not always orbital radius

If a question gives the height above Earth’s surface, that is not the orbital radius. The orbital radius is measured from Earth’s centre, so you must add Earth’s radius if it is needed.

Common Mistake

Circular orbit assumption

The equation v=2×π×rTv = \frac{2 \times \pi \times r}{T}v=T2×π×r​ is for circular orbits. For very elliptical orbits, like many comets, the speed changes during the orbit.

Exam technique

In the exam

  1. Learn the hierarchy clearly: Universe contains galaxies, galaxies contain stars, and our Solar System is in the Milky Way.
  2. For orbit questions, always show gravity acting towards the central body and velocity tangent to the orbit.
  3. For orbital speed calculations, convert units first, use the orbital radius not the diameter, and give the final answer with units.
Self review

Check yourself

  • Why is your weight different on the Moon but your mass is unchanged?
  • In what direction does gravity act on a planet orbiting the Sun?
  • A satellite’s orbital radius and time period are given. Which equation would you use to calculate its orbital speed?
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Nested diagram showing the Universe containing many galaxies, the Milky Way, the Solar System, and Earth

The Universe is everything that exists: all space, matter and energy. It contains huge numbers of galaxies, and our Solar System is inside just one of them.

A galaxy is a vast collection of stars held together by gravity. Our galaxy is the Milky Way, and the Solar System is the Sun plus the planets, moons, comets and satellites that orbit it.

Earth is one planet in that Solar System. A useful hierarchy to learn is: Universe →\rightarrow→ galaxies →\rightarrow→ Milky Way galaxy →\rightarrow→ Solar System →\rightarrow→ Earth.

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What is a galaxy?

Motion in the universe Revision Guide

  1. IGCSE
  2. /Physics
  3. /Motion in the universe