A student prepares lead iodide by mixing solutions of lead nitrate and potassium iodide.
Pb(NO3)2(aq)+2KI(aq)→PbI2(s)+2KNO3(aq)\mathrm{Pb(NO_3)_2(aq) + 2KI(aq) \rightarrow PbI_2(s) + 2KNO_3(aq)}Pb(NO3)2(aq)+2KI(aq)→PbI2(s)+2KNO3(aq)
The student uses 0.0400 mol of potassium iodide and excess lead nitrate. The percentage yield of pure, dry lead iodide is 80.0%.
What is the mass of lead iodide collected?
(Relative atomic masses: I = 127, Pb = 207)
1.84 g1.84\,\mathrm{g}1.84g
7.38 g7.38\,\mathrm{g}7.38g
9.22 g9.22\,\mathrm{g}9.22g
14.8 g14.8\,\mathrm{g}14.8g
151 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.