A student heats 6.20 g of copper(II) carbonate and obtains 3.60 g of copper(II) oxide. CuCO3(s)→CuO(s)+CO2(g)\mathrm{CuCO_{3}(s) \rightarrow CuO(s) + CO_{2}(g)}CuCO3(s)→CuO(s)+CO2(g)
What is the percentage yield? (Relative atomic masses: C = 12, O = 16, Cu = 63.5)
37.4%
58.1%
90.2%
111%
51 exam-style questions on Edexcel GCSE Chemistry 6.2 Quantitative analysis, covering 6.2.1 Concentration in mol dm⁻³ and titration calculations, 6.2.2 Percentage yield and why actual yield falls short, 6.2.3 Atom economy of a reaction, 6.2.4 Choosing a reaction pathway, and 6.2.5 Molar volume of gases and Avogadro's law. Each one has a worked solution and a mark scheme showing where the marks go.