A student investigates the neutralisation reaction between sodium hydroxide and hydrochloric acid:
NaOH (aq)+HCl (aq)→NaCl (aq)+H2O (l) \text{NaOH (aq)} + \text{HCl (aq)} \rightarrow \text{NaCl (aq)} + \text{H}_2\text{O (l)} NaOH (aq)+HCl (aq)→NaCl (aq)+H2O (l)The student mixes 0.85 moles0.85\text{ moles}0.85 moles of sodium hydroxide with 0.62 moles0.62\text{ moles}0.62 moles of hydrochloric acid.
Show that the sodium hydroxide is in excess.
