Ethanoic acid reacts with magnesium to form a salt and a gas. The ethanoate ion is CH3COO−\mathrm{CH_{3}COO^{-}}CH3COO− and the magnesium ion is Mg2+\mathrm{Mg^{2+}}Mg2+.
Which equation is correct?
2CH3COOH+Mg→Mg(CH3COO)2+H2\mathrm{2CH_{3}COOH + Mg \rightarrow Mg(CH_{3}COO)_{2} + H_{2}}2CH3COOH+Mg→Mg(CH3COO)2+H2
2CH3COOH+2Mg→2MgCH3COO+H2\mathrm{2CH_{3}COOH + 2Mg \rightarrow 2MgCH_{3}COO + H_{2}}2CH3COOH+2Mg→2MgCH3COO+H2
2CH3COOH+Mg→Mg(CH3COO)2+H2O\mathrm{2CH_{3}COOH + Mg \rightarrow Mg(CH_{3}COO)_{2} + H_{2}O}2CH3COOH+Mg→Mg(CH3COO)2+H2O
4CH3COOH+Mg→Mg(CH3COO)4+2H2\mathrm{4CH_{3}COOH + Mg \rightarrow Mg(CH_{3}COO)_{4} + 2H_{2}}4CH3COOH+Mg→Mg(CH3COO)4+2H2
43 exam-style questions on Edexcel GCSE Chemistry 10.4 Alcohols and carboxylic acids, covering 10.4.1 Alcohols and the -OH functional group, 10.4.2 Carboxylic acids and the -COOH functional group, 10.4.3 Oxidation of alcohols and homologous series, and 10.4.4 Fermentation and fractional distillation of ethanol. Each one has a worked solution and a mark scheme showing where the marks go.