3.2.4 Limiting reactants
One reactant runs out first and halts the reaction
Limiting reactant
The reactant that is completely used up in a reaction, so it controls the maximum amount of product that can form.
- Reactants are rarely mixed in the exact ratio of the equation, so usually one is used up before the other.
- The reactant that runs out first is the limiting reactant, and the reaction stops once it is gone.
- The other reactant is in excess, so some of it is left over unreacted.
Adding more of the excess reactant makes no extra product, because there is no limiting reactant left for it to react with.
The limiting reactant fixes how much product forms
Product
A product is a substance formed during a chemical reaction.
- The amount of product is directly proportional to the amount of the limiting reactant.
- Doubling the limiting reactant doubles the product, while the excess reactant has no effect on the yield.
If magnesium runs out while acid is left over, adding more acid produces no extra hydrogen, but adding more magnesium would.
Finding which reactant is limiting
Mole
The amount of a substance, measured in mol, where one mole has a mass in grams numerically equal to its relative formula mass.
- Convert the mass of each reactant into moles.
- Use the mole ratio in the equation to see which reactant is in short supply.
- Base every amount-of-product calculation on the limiting reactant only.
- Compare reactants in moles, never in grams, because the equation ratio is a ratio of moles.
- State clearly which reactant is limiting before you work out the product, so your reasoning is easy to follow.
Worked example: making water from hydrogen and oxygen
- 4 g4\ \text{g}4 g of hydrogen and 40 g40\ \text{g}40 g of oxygen react in 2H2+O2→2H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}2H2+O2→2H2O.
- This is 42=2 mol\dfrac{4}{2} = 2\ \text{mol}24=2 mol of hydrogen and 4032=1.25 mol\dfrac{40}{32} = 1.25\ \text{mol}3240=1.25 mol of oxygen.
- The 2 mol2\ \text{mol}2 mol of hydrogen needs only 1 mol1\ \text{mol}1 mol of oxygen, so hydrogen is limiting and oxygen is in excess.
- The 2 mol2\ \text{mol}2 mol of hydrogen makes 2 mol2\ \text{mol}2 mol of water, which is 2×18=36 g2 \times 18 = 36\ \text{g}2×18=36 g.
- What is meant by the limiting reactant?
- Why does adding more of the excess reactant not make more product?
- How do you decide which reactant is limiting?
- In the worked example, why is oxygen described as being in excess?