3.2.5a Concentration of solutions
Concentration measures how much solute is packed into a solution
Solution
A mixture formed when a solute dissolves in a solvent.
Solute
The substance dissolved in a solvent to form a solution.
- Many reactions take place in solution, so it helps to describe how much dissolved substance a solution contains.
- A solute dissolves in a solvent to make the solution.
- The concentration tells you how much solute is present in a given volume of that solution.
- More solute in the same volume makes a more concentrated solution.
- The same solute spread through a larger volume makes a more dilute solution.
Mass concentration is measured in grams per cubic decimetre
Concentration
The mass of solute present per unit volume of solution, usually measured in g/dm3\text{g}/\text{dm}^3g/dm3 for this calculation.
- Concentration in g/dm3\text{g}/\text{dm}^3g/dm3 is the mass of solute divided by the volume of solution, or c=mVc = \dfrac{m}{V}c=Vm.
- Here mmm is the mass of solute in grams and VVV is the volume of solution in dm3\text{dm}^3dm3.
Dissolving 20 g20\ \text{g}20 g of salt in 0.5 dm30.5\ \text{dm}^30.5 dm3 of water gives a concentration of 200.5=40 g/dm3\dfrac{20}{0.5} = 40\ \text{g}/\text{dm}^30.520=40 g/dm3.
Convert the volume from cm3cm^3cm3 to dm3dm^3dm3 before you start
- One cubic decimetre equals 1000 cm31000\ \text{cm}^31000 cm3, so divide a volume in cm3\text{cm}^3cm3 by 100010001000 to get dm3\text{dm}^3dm3.
- For example, 250 cm3250\ \text{cm}^3250 cm3 is 2501000=0.25 dm3\dfrac{250}{1000} = 0.25\ \text{dm}^31000250=0.25 dm3.
- Convert every volume to dm3\text{dm}^3dm3 first, as using cm3\text{cm}^3cm3 makes the concentration a thousand times too small.
- Always write the unit g/dm3\text{g}/\text{dm}^3g/dm3 with a mass concentration answer.
Finding the mass of solute in a solution
- Rearranging the formula gives the mass of solute as m=c×Vm = c \times Vm=c×V.
- For 250 cm3250\ \text{cm}^3250 cm3 of a 40 g/dm340\ \text{g}/\text{dm}^340 g/dm3 solution, first write the volume as 0.25 dm30.25\ \text{dm}^30.25 dm3.
- The mass of solute is 40×0.25=10 g40 \times 0.25 = 10\ \text{g}40×0.25=10 g.
- What does the concentration of a solution tell you?
- How do you convert a volume in cm3\text{cm}^3cm3 into dm3\text{dm}^3dm3?
- Find the concentration when 30 g30\ \text{g}30 g of solute is dissolved to make 2 dm32\ \text{dm}^32 dm3 of solution.
- What mass of solute is in 500 cm3500\ \text{cm}^3500 cm3 of a 20 g/dm320\ \text{g}/\text{dm}^320 g/dm3 solution?
3.2.5b Relating mass, volume and concentration
Concentration, solute mass and volume are tied together
Concentration
The mass of solute present per unit volume of solution, usually measured in g/dm3\text{g}/\text{dm}^3g/dm3 for this calculation.
- The three quantities are linked by c=mVc = \dfrac{m}{V}c=Vm, so knowing any two lets you find the third.
- Concentration ccc is in g/dm3\text{g}/\text{dm}^3g/dm3, mass mmm is in grams and volume VVV is in dm3\text{dm}^3dm3.
Concentration goes up when you add solute and goes down when you add solvent, because it is a mass shared over a volume.
More solute raises the concentration
Solute
The substance dissolved in a solvent to form a solution.
- At a fixed volume, concentration is directly proportional to the mass of solute.
- Doubling the mass of solute in the same volume doubles the concentration.
Going from 10 g10\ \text{g}10 g to 20 g20\ \text{g}20 g of solute in 1 dm31\ \text{dm}^31 dm3 raises the concentration from 101010 to 20 g/dm320\ \text{g}/\text{dm}^320 g/dm3.
A larger volume lowers the concentration
Solution
A mixture formed when a solute dissolves in a solvent.
- At a fixed mass of solute, concentration is inversely proportional to the volume of solution.
- Adding more solvent dilutes the solution, so the same solute spread through a bigger volume gives a lower concentration.
- When asked to explain a change, name which quantity you kept fixed and which you changed.
- Check the volume is in dm3\text{dm}^3dm3 before rearranging, or the mass or volume you find will be wrong by a factor of a thousand.
Rearranging to find a mass or a volume
- To find a mass of solute, use m=c×Vm = c \times Vm=c×V.
- In 200 cm3200\ \text{cm}^3200 cm3 (0.2 dm30.2\ \text{dm}^30.2 dm3) of a 15 g/dm315\ \text{g}/\text{dm}^315 g/dm3 solution, the mass of solute is 15×0.2=3 g15 \times 0.2 = 3\ \text{g}15×0.2=3 g.
- To find a volume, use V=mcV = \dfrac{m}{c}V=cm.
- A 25 g/dm325\ \text{g}/\text{dm}^325 g/dm3 solution holds 10 g10\ \text{g}10 g of solute in 1025=0.4 dm3\dfrac{10}{25} = 0.4\ \text{dm}^32510=0.4 dm3, which is 400 cm3400\ \text{cm}^3400 cm3.
- How does increasing the mass of solute change the concentration at fixed volume?
- Why does diluting a solution with water lower its concentration?
- What mass of solute is in 100 cm3100\ \text{cm}^3100 cm3 of a 30 g/dm330\ \text{g}/\text{dm}^330 g/dm3 solution?
- What volume of a 50 g/dm350\ \text{g}/\text{dm}^350 g/dm3 solution contains 20 g20\ \text{g}20 g of solute?
