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3.2.5 Concentration of solutions

3.2.5a Concentration of solutions

Concentration measures how much solute is packed into a solution

Definition

Solution

A mixture formed when a solute dissolves in a solvent.

Definition

Solute

The substance dissolved in a solvent to form a solution.

  1. Many reactions take place in solution, so it helps to describe how much dissolved substance a solution contains.
  2. A solute dissolves in a solvent to make the solution.
  3. The concentration tells you how much solute is present in a given volume of that solution.
Key Idea
  • More solute in the same volume makes a more concentrated solution.
  • The same solute spread through a larger volume makes a more dilute solution.

Mass concentration is measured in grams per cubic decimetre

Definition

Concentration

The mass of solute present per unit volume of solution, usually measured in g/dm3\text{g}/\text{dm}^3g/dm3 for this calculation.

  1. Concentration in g/dm3\text{g}/\text{dm}^3g/dm3 is the mass of solute divided by the volume of solution, or c=mVc = \dfrac{m}{V}c=Vm​.
  2. Here mmm is the mass of solute in grams and VVV is the volume of solution in dm3\text{dm}^3dm3.
Example

Dissolving 20 g20\ \text{g}20 g of salt in 0.5 dm30.5\ \text{dm}^30.5 dm3 of water gives a concentration of 200.5=40 g/dm3\dfrac{20}{0.5} = 40\ \text{g}/\text{dm}^30.520​=40 g/dm3.

Convert the volume from cm3cm^3cm3 to dm3dm^3dm3 before you start

  1. One cubic decimetre equals 1000 cm31000\ \text{cm}^31000 cm3, so divide a volume in cm3\text{cm}^3cm3 by 100010001000 to get dm3\text{dm}^3dm3.
  2. For example, 250 cm3250\ \text{cm}^3250 cm3 is 2501000=0.25 dm3\dfrac{250}{1000} = 0.25\ \text{dm}^31000250​=0.25 dm3.
Exam technique
  • Convert every volume to dm3\text{dm}^3dm3 first, as using cm3\text{cm}^3cm3 makes the concentration a thousand times too small.
  • Always write the unit g/dm3\text{g}/\text{dm}^3g/dm3 with a mass concentration answer.

Finding the mass of solute in a solution

  1. Rearranging the formula gives the mass of solute as m=c×Vm = c \times Vm=c×V.
  2. For 250 cm3250\ \text{cm}^3250 cm3 of a 40 g/dm340\ \text{g}/\text{dm}^340 g/dm3 solution, first write the volume as 0.25 dm30.25\ \text{dm}^30.25 dm3.
    1. The mass of solute is 40×0.25=10 g40 \times 0.25 = 10\ \text{g}40×0.25=10 g.
Self review
  • What does the concentration of a solution tell you?
  • How do you convert a volume in cm3\text{cm}^3cm3 into dm3\text{dm}^3dm3?
  • Find the concentration when 30 g30\ \text{g}30 g of solute is dissolved to make 2 dm32\ \text{dm}^32 dm3 of solution.
  • What mass of solute is in 500 cm3500\ \text{cm}^3500 cm3 of a 20 g/dm320\ \text{g}/\text{dm}^320 g/dm3 solution?

3.2.5b Relating mass, volume and concentration

Concentration, solute mass and volume are tied together

Definition

Concentration

The mass of solute present per unit volume of solution, usually measured in g/dm3\text{g}/\text{dm}^3g/dm3 for this calculation.

  1. The three quantities are linked by c=mVc = \dfrac{m}{V}c=Vm​, so knowing any two lets you find the third.
  2. Concentration ccc is in g/dm3\text{g}/\text{dm}^3g/dm3, mass mmm is in grams and volume VVV is in dm3\text{dm}^3dm3.
Key Idea

Concentration goes up when you add solute and goes down when you add solvent, because it is a mass shared over a volume.

More solute raises the concentration

Definition

Solute

The substance dissolved in a solvent to form a solution.

  1. At a fixed volume, concentration is directly proportional to the mass of solute.
  2. Doubling the mass of solute in the same volume doubles the concentration.
Example

Going from 10 g10\ \text{g}10 g to 20 g20\ \text{g}20 g of solute in 1 dm31\ \text{dm}^31 dm3 raises the concentration from 101010 to 20 g/dm320\ \text{g}/\text{dm}^320 g/dm3.

A larger volume lowers the concentration

Definition

Solution

A mixture formed when a solute dissolves in a solvent.

  1. At a fixed mass of solute, concentration is inversely proportional to the volume of solution.
  2. Adding more solvent dilutes the solution, so the same solute spread through a bigger volume gives a lower concentration.
Exam technique
  • When asked to explain a change, name which quantity you kept fixed and which you changed.
  • Check the volume is in dm3\text{dm}^3dm3 before rearranging, or the mass or volume you find will be wrong by a factor of a thousand.

Rearranging to find a mass or a volume

  1. To find a mass of solute, use m=c×Vm = c \times Vm=c×V.
    1. In 200 cm3200\ \text{cm}^3200 cm3 (0.2 dm30.2\ \text{dm}^30.2 dm3) of a 15 g/dm315\ \text{g}/\text{dm}^315 g/dm3 solution, the mass of solute is 15×0.2=3 g15 \times 0.2 = 3\ \text{g}15×0.2=3 g.
  2. To find a volume, use V=mcV = \dfrac{m}{c}V=cm​.
    1. A 25 g/dm325\ \text{g}/\text{dm}^325 g/dm3 solution holds 10 g10\ \text{g}10 g of solute in 1025=0.4 dm3\dfrac{10}{25} = 0.4\ \text{dm}^32510​=0.4 dm3, which is 400 cm3400\ \text{cm}^3400 cm3.
Self review
  • How does increasing the mass of solute change the concentration at fixed volume?
  • Why does diluting a solution with water lower its concentration?
  • What mass of solute is in 100 cm3100\ \text{cm}^3100 cm3 of a 30 g/dm330\ \text{g}/\text{dm}^330 g/dm3 solution?
  • What volume of a 50 g/dm350\ \text{g}/\text{dm}^350 g/dm3 solution contains 20 g20\ \text{g}20 g of solute?
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Comparison of solutions showing that more solute in the same volume increases concentration, while the same mass of solute in a larger volume decreases concentration

A solution forms when a solute dissolves in a solvent. Concentration measures how much solute is present in a given volume of the solution.

Adding solute without changing the volume increases concentration. Adding solvent spreads the same solute through a larger volume, producing a more dilute solution.

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What forms when a solute dissolves in a solvent?

3.2.5 Concentration of solutions Revision Guide

  1. GCSE
  2. /Chemistry
  3. /3.2.5 Concentration of solutions

Revision notes for AQA GCSE Chemistry 3.2.5 Concentration of solutions. Open the guide for explanations and worked examples. Written against the AQA GCSE Chemistry (8462) specification, so the content matches what's examinable rather than general Chemistry background.

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