During the electrolysis of dilute sulfuric acid, water is decomposed into hydrogen and oxygen.
Complete the half-equation for the oxidation of hydroxide ions at the positive electrode (anode): 4OH−→2H2O+O2+‾e−4\text{OH}^- \rightarrow 2\text{H}_2\text{O} + \text{O}_2 + \underline{\quad} \text{e}^-4OH−→2H2O+O2+e−
The overall chemical equation for the electrolysis of water is: 2H2O(l)→2H2(g)+O2(g)2\text{H}_2\text{O}(\text{l}) \rightarrow 2\text{H}_2(\text{g}) + \text{O}_2(\text{g})2H2O(l)→2H2(g)+O2(g)
If 56 cm356\text{ cm}^356 cm3 of hydrogen gas is collected at the negative electrode, what volume of oxygen gas is collected at the positive electrode under the same conditions of temperature and pressure?